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前言 
利用 reduce 函数实现。
需求如下 
对于如下对象列表:
python
[
    {'name':'black','foo':123},
    {'name':'black','foo':456},
    {'name':'white','foo':789},
]期望得到:
python
[
    {'name':'black','foo':123}, # 或保留 {'name':'black','foo':456},这不重要
    {'name':'white','foo':789},
]Show Me The Code 
当时思索了一通,实现压缩到最简,如下:
python
a = [
    {'name':'black','foo':123},
    {'name':'black','foo':456},
    {'name':'white','foo':789}
]
result = reduce(lambda y,x:y if (x['name'] in [i['name'] for i in y]) else (lambda z,u:(z.append(u),z))(y,x)[1],a,[])此外 
reduce 函数在 functools 模块中:
python
from functools import reduce